Timeline for Removing non-basepoint from linear sytem.
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Jul 11, 2011 at 16:57 | comment | added | Francesco Polizzi | Since $P_n$ is not a base point of $|D|$, there is a section of $H^0(D)$ that does not vanish in $P_n$. So the inclusion $H^0(D-P_n) \subset H^0(D)$ is strict. On the other hand, imposing the passage through a point is at most one linear condition, so $H^0(D-P_n)$ has codimension exactly $1$ in $H^0(D)$. | |
| Jul 11, 2011 at 16:48 | answer | added | Mike Skirvin | timeline score: 1 | |
| Jul 11, 2011 at 16:35 | history | asked | phil | CC BY-SA 3.0 |