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Jul 11, 2011 at 9:54 comment added Goldstern From mathoverflow.net/questions/44326 : deweger.xs4all.nl/papers/…
Jul 11, 2011 at 1:34 comment added Joseph O'Rourke Pinter and deWeger, "$210 = 14 \times 15 = 5 \times 6 \times 7 = \binom{21}{4} = \binom{10}{4}$". Publ. Math. Debrecen. 51(1-2) 175-189 (1997). "It is given all the solutions to the Diophantine equations $(y−1)y(y+1)=\binom{n}{4}$ and $x (x+1) = \binom{n}{4}$."
Jul 11, 2011 at 1:33 comment added user9072 That's a nice one. I heard of this once, but completely forgot. Nice to be reminded.
Jul 11, 2011 at 1:20 history answered Gerhard Paseman CC BY-SA 3.0