Timeline for Subtract diagonal terms from the matrix to make it negative semi-definite
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Jul 7, 2011 at 18:11 | comment | added | Robert Israel | More general in what way? Perhaps subtracting $d_i$ from $M_{i,i}$ for each $i$? Then if $\min_i d_i \ge \max_j \lambda_j$, the new matrix will be negative semidefinite. | |
Jul 6, 2011 at 19:17 | comment | added | sbos | Ok, let M be symmetrical matrix | |
Jul 6, 2011 at 19:02 | comment | added | sbos | That's nice, but what would be in more general case? | |
Jul 6, 2011 at 16:21 | history | answered | Robert Israel | CC BY-SA 3.0 |