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Jul 31, 2017 at 16:40 comment added Joseph O'Rourke @PerAlexandersson : Perhaps one could shift the pegs slightly to obtain the correct weighting.
Jul 31, 2017 at 13:08 comment added Per Alexandersson If all balls are dropped from the center, any pin configuration would put half of the mass on either side of the center, or am I mistaken? Thus, you might need to allow dropping balls from several locations, which defeats the purpose a bit I suppose... Perhaps one can allow ball sources to be equal the number of peaks or something...
Jul 31, 2017 at 11:49 history edited Joseph O'Rourke CC BY-SA 3.0
deleted 48 characters in body; edited tags; edited title
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jul 6, 2011 at 20:27 history edited Joseph O'Rourke CC BY-SA 3.0
Labeled the final question and added history tag, as that aspect has attracted some interest...
Jul 6, 2011 at 20:24 comment added Anthony Quas PS: Hawking would be recognizable...
Jul 6, 2011 at 20:23 comment added Anthony Quas If you take a convolution of your favourite smooth function with a normal distribution with mean 0 and small standard deviation, then you get essentially your function back. This convolution though can be approximated by a finite mixture of normal distributions.
Jul 6, 2011 at 18:44 answer added Gerhard Paseman timeline score: 2
Jul 6, 2011 at 18:41 comment added Douglas Zare For Q1, there are restrictions beyond positivity even for smooth functions if you want equality. The tails of any convex combination of normal distributions do not drop too rapidly, so $\exp(-x^4)$ is not a convex combination of normal distributions. You might approximate it arbitrarily well, though.
Jul 6, 2011 at 16:39 comment added drbobmeister Most people won't even recognize Newton!
Jul 6, 2011 at 14:31 comment added Qiaochu Yuan Nice question! But would people recognize any mathematician's face aside from, perhaps, Newton?
Jul 6, 2011 at 13:21 history asked Joseph O'Rourke CC BY-SA 3.0