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Jul 13, 2011 at 2:26 history edited Vipul Naik CC BY-SA 3.0
Fixed an incorrect side statement which claimed that the "character determines the representation"
Jul 8, 2011 at 22:30 vote accept Vipul Naik
Jul 8, 2011 at 2:07 answer added David E Speyer timeline score: 11
Jul 6, 2011 at 0:09 comment added François Brunault There are examples of outer automorphisms $\varphi : G \to G$ such that for all $g \in G$, $\varphi(g)$ is conjugate to $g$. Maybe composing a faithful representation with such an automorphism could give a counterexample to Question 2 ?
Jul 5, 2011 at 23:48 answer added Alex Eskin timeline score: 23
Jul 5, 2011 at 23:04 comment added Geoff Robinson I think you are awfully close with the Klein 4 example. The idea, as you probably know already, would be to construct a representation which is free for every cyclic subgroup, but not free for the Klein 4-group itself. Then the representation would locally conjugate, bout not equivalent, to a free representation.
Jul 5, 2011 at 22:42 history asked Vipul Naik CC BY-SA 3.0