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Jul 5, 2011 at 22:22 vote accept Will Jagy
Jul 4, 2011 at 20:55 comment added Will Jagy I sent you an email, I'm holding a copy of the first edition of SPLAG. Let's see, they say the deep holes in the Leech lattice have a one-to-one correspondence with the Niemeier lattices, page 413. In Chapter 23 on the covering radius of the Leech lattice, Theorem 2 says there are 23 inequivalent deep holes in the Leech lattice, these correspond with the other 23 Niemeier lattices.
Jul 4, 2011 at 19:48 comment added Noam D. Elkies Come to think of it, if $L = E_8$ then for each deep hole $L' = D_8$, so that's already a counterexample to $L'=L$ — though here $[L:L']=2$ so we can't get an extra odd factor in the denominator, and as it happens the covering radius is 1 so there's no denominator at all. [If we construct $E_8$ as the union of $D_8$ with its shift by $(\frac12,\frac12,\ldots,\frac12)$ then all deep holes are equivalent to $(1,0,0,\ldots,0)$.] What happens for the Leech lattice? I don't have a copy of SPLAG handy today...
Jul 4, 2011 at 4:07 comment added Noam D. Elkies The "classes in the genus of the Leech lattice" are the 24 Niemeier lattices, right?
Jul 4, 2011 at 3:30 comment added Will Jagy Oh, and the part about class number one refers to strict inequality, otherwise the Leech lattice would be included. I don't know the number of classes in the genus of the Leech lattice, however it is not one.
Jul 4, 2011 at 2:33 comment added Will Jagy Thanks, Noam. All examples are in dimension 10 or less. Also, all Pete's examples have class number one, and it is a result of George Leo Watson that this implies dimension no larger than 10. I have been searching for some time for an a priori proof of class number one, no luck.
Jul 4, 2011 at 2:23 history answered Noam D. Elkies CC BY-SA 3.0