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Jul 5, 2011 at 17:23 comment added Andrew Parker @Yves, thanks for your clarification re projectivity & FG. I was considering exactly what you are referencing in your first remark, that $M \otimes R_P \equiv R_P$ for all primes $P$ as my 'definition' for invertibility.
Jul 5, 2011 at 17:17 vote accept Andrew Parker
Jul 3, 2011 at 20:43 history answered YCor CC BY-SA 3.0