Timeline for Integration by parts for a general negative-definite self-adjoint operator.
Current License: CC BY-SA 3.0
14 events
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Jul 11, 2011 at 21:22 | vote | accept | CommunityBot | ||
Jul 11, 2011 at 21:22 | history | bounty ended | RadonNikodym | ||
Jul 7, 2011 at 20:28 | answer | added | Helge | timeline score: 0 | |
Jul 7, 2011 at 15:12 | comment | added | Helge | Of course not. $Lf$ is not defined. | |
Jul 7, 2011 at 14:13 | comment | added | RadonNikodym | The question is: Given f with the properties specified can I write $(-Lf,f)$ as $\int \nabla f \cdot A(x) \nabla f \pi(dx)$ | |
Jul 7, 2011 at 3:46 | comment | added | Helge | What is the question? I just read it three times, and am not sure what the question is. My best guess is: "What does $f\in D((-L)^(1/2))$ mean?" | |
Jul 6, 2011 at 17:09 | answer | added | Jeff Schenker | timeline score: 1 | |
Jul 4, 2011 at 21:37 | answer | added | paul garrett | timeline score: 4 | |
Jul 4, 2011 at 20:24 | history | bounty started | RadonNikodym | ||
Jun 30, 2011 at 15:19 | comment | added | RadonNikodym | @Florian. Yes I would to know of results where $\pi$ is as general as possible (for example the underlying $\sigma$-algebra$ not necessarily countably generated, etc) | |
Jun 30, 2011 at 15:16 | history | edited | RadonNikodym | CC BY-SA 3.0 |
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Jun 30, 2011 at 15:14 | comment | added | RadonNikodym | Yes, actually I should have mentioned that assumption also. Thanks for pointing this out. | |
Jun 30, 2011 at 15:11 | comment | added | Florian | Am I right that you want to study this problem in the abstract (i.e. $\pi$ is a measure on some unspecified measurable space etc.)? Then your assumption that the operators $D_i$ are only skew-Hermitian seems too weak to me. A more natural assumption would be that the $D_i$ are skew-adjoint, that is, the domain of the adjoint $D_i^*$ equals that of $D_i$ (in addition to the skew-symmetry). | |
Jun 30, 2011 at 12:11 | history | asked | RadonNikodym | CC BY-SA 3.0 |