Timeline for On the field of invariants of a finite group
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Jul 2, 2011 at 16:01 | comment | added | Geoff Robinson | Do you mean to assume transitivity of $G$? For example, if $n = 4$, a Klein 4-group $V$ can be embedded in $S_4$ in two quite different ways. One as the unique normal subgroup of order $4$ of $S_4$ which is regular (and, in particular transitive). In this case $V$ is eembedded as $\langle (1), (12)(34),(13)(24),(14)23) \langle$. Alternatively, $V$ may be embedded as $\langle (1),(12),(34),(12)(34) \rangle$, which is an intransitive subgroup of $S_4$. | |
| Jun 29, 2011 at 4:18 | answer | added | Torsten Ekedahl | timeline score: 6 | |
| Jun 29, 2011 at 3:40 | answer | added | JSE | timeline score: 2 | |
| Jun 29, 2011 at 1:19 | history | edited | Hugo Chapdelaine | CC BY-SA 3.0 |
added 14 characters in body
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| Jun 29, 2011 at 1:01 | comment | added | Hugo Chapdelaine | Yes this what I meant, I just changed it | |
| Jun 29, 2011 at 1:00 | history | edited | Hugo Chapdelaine | CC BY-SA 3.0 |
deleted 2 characters in body
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| Jun 29, 2011 at 0:41 | comment | added | Andreas Blass |
You presumably meant that the transcendence degree of $L^G$ over $K$ is $n$, not $|G|$.
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| Jun 29, 2011 at 0:30 | history | asked | Hugo Chapdelaine | CC BY-SA 3.0 |