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Dec 23, 2011 at 17:30 answer added Emily Riehl timeline score: 6
Jun 28, 2011 at 2:15 comment added Mikhail Gudim Maybe one should ask this question instead: Let $F:A \to B$ be an additive left-exact functor of abelian categories (do not assume that they have enough injectives / projectives. Suppose we are given a class of objects $R$ adapted to $F$. Is there a closed model category structure on $Com^+(A)$ such that weak equivalences are quasi-isomorphisms and $R$ is (or contains) the class of cofibrant objects. If the answer to this question is "yes", then I guess this gives an answer to the original question. But maybe the original question has other solutions...?
Jun 28, 2011 at 2:05 comment added Mikhail Gudim Derived functors are defined by universal properties without any choices. Their existence is proven using cofibrant replacements which exist by axioms of closed model category (sorry, above by a "model category" I actually meant closed model category) and certain properties of the functor $F$ itself.
Jun 28, 2011 at 1:55 comment added Mikhail Gudim Here is the definition of class of objects $R$ adapted to a left exact functor $F:A \to B$ (from Gelfand and Manin): $R$ is closed under finite direct sums, $F$ maps acyclic complex from $Com^+(R)$ into an acyclic complex, any object from $A$ is a subobject of an object from $R$.
Jun 27, 2011 at 23:44 comment added David White This doesn't answer your question, but it's a comment that often it's better to define derived functors so they only depend on $\mathcal{C}$ not on a choice of cofibrant replacement. I suppose your way would allow easier computation but might lose a lot by making that choice. A good reference is this page of Hovey's book: books.google.com/…
Jun 27, 2011 at 23:35 comment added David White Just to confirm, you're looking at $Ch(\mathcal{A})$ where $\mathcal{A}$ is an abelian category with enough projectives and injectives? Based on the article I linked above, those seem to be prerequisites for your fact about adapted objects being used to compute derived functors. I don't think a model category $\mathcal{C}$ needs to have enough projectives. In general cofibrant replacement is not the same as projective resolution. See e.g. mathoverflow.net/questions/10246/…
Jun 27, 2011 at 23:14 comment added David White I had to look this up, so I figured I'd comment to help others. Adapted Object: ncatlab.org/nlab/show/class+of+adapted+objects
Jun 27, 2011 at 22:39 history asked Mikhail Gudim CC BY-SA 3.0