Timeline for How does one view the De Rham spectral sequence as a Grothendieck spectral sequence?
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8 events
| when toggle format | what | by | license | comment | |
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| Jun 28, 2011 at 22:55 | vote | accept | James D. Taylor | ||
| Jun 27, 2011 at 6:44 | comment | added | Torsten Ekedahl | Dan's point is excellent, I do not know of any nice interpretation of the $E_2$-term of the Hodge-de Rham spectral sequence which would come out of a composed functor interpretation (hence acting as an argument against such an interpretation). | |
| Jun 27, 2011 at 6:18 | comment | added | Dan Petersen | In addition to what Mariano and Torsten have said, the Hodge-de Rham spectral sequence starts at $E_1$ and the Grothendieck spectral sequence starts at $E_2$. Hence it's unlikely that the former would be a special case of the latter. | |
| Jun 27, 2011 at 5:49 | answer | added | Mariano Suárez-Álvarez | timeline score: 7 | |
| Jun 27, 2011 at 5:42 | answer | added | Torsten Ekedahl | timeline score: 6 | |
| Jun 27, 2011 at 5:13 | comment | added | Mikhail Bondarko | As far as I remember. the de Rham compleX is the hyper-resolution of the constant sheaf in the infinitesimal topology; see webcache.googleusercontent.com/… | |
| Jun 27, 2011 at 3:00 | comment | added | David Roberts♦ | A naive comment: find the resolution, and this will give you the derived functor. | |
| Jun 27, 2011 at 2:36 | history | asked | James D. Taylor | CC BY-SA 3.0 |