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Nov 15, 2012 at 3:10 comment added Emerton ... and you shouldn't be very concerned about possible differences in usage. Regards, Matthew
Nov 15, 2012 at 3:04 comment added Emerton Dear Davidac, As Paul Garrett says, "all are true". On the one hand, $\zeta$-functions are traditionally associated to the trivial Galois representation, or an entire scheme of finite type over $\mathbb Z$ (or its cohomology with trivial coefficients, if one wants to think sheaf-theoretically), while $L$-functions are what happens when you allow ``twists'' in what would otherwise be $\zeta$-functions (think of Dirichlet $L$-functions compared to the Riemann $\zeta$-function), such as non-trivial Galois reps., or non-trivial sheaves, etc. But there is no hard and fast rule. ...
Nov 14, 2012 at 19:44 comment added Will Sawin There is a reason that Prof. Nick Katz's course this semester is on equidistribution of L-functions over finite fields at not equidistribution of zeta functions over finite fields.
Nov 14, 2012 at 19:00 comment added paul garrett It is likely that "all are true", I think... as in my add-on answer below.
Nov 14, 2012 at 18:59 answer added paul garrett timeline score: 11
Nov 14, 2012 at 18:08 comment added David Corwin Currently, I feel like there is no consensus among the answers, with Hansen's and Buzzard's answers reflecting one view, and engelbrekt and Will Sawin's reflecting another.
Nov 14, 2012 at 18:06 history edited David Corwin CC BY-SA 3.0
edited body
Nov 14, 2012 at 17:25 answer added Will Sawin timeline score: 9
Dec 9, 2009 at 14:24 vote accept David Corwin
Nov 27, 2009 at 19:25 answer added Kevin Buzzard timeline score: 18
Nov 27, 2009 at 19:18 history edited Ilya Nikokoshev
retag
Nov 27, 2009 at 3:59 answer added David Hansen timeline score: 24
Nov 26, 2009 at 16:45 answer added engelbrekt timeline score: 13
Nov 26, 2009 at 15:03 history asked David Corwin CC BY-SA 2.5