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May 16, 2016 at 9:03 vote accept IMeasy
Apr 19, 2016 at 16:09 comment added Ben McKay The Pfaffian of a skew symmetric matrix is a polynomial in the entries of the matrix, whose square is the determinant of the matrix, as given in your explicit formula. But the Pfaffian of a real matrix can be positive or negative, so the Pfaffian is not the square root, but only one of the two square roots, of the determinant.
S Apr 19, 2016 at 16:04 history suggested Amir Sagiv CC BY-SA 3.0
edited the tags. added pfaffian tag. commutative algebra and algebraic geometry are too loosely related
Apr 19, 2016 at 15:32 review Suggested edits
S Apr 19, 2016 at 16:04
Jun 26, 2011 at 19:14 answer added Hailong Dao timeline score: 5
Jun 26, 2011 at 17:43 comment added IMeasy I am sorry for the sloppyness of the question. I assumed, without stating, that the matrix had linear entries. Now I've edited it.
Jun 26, 2011 at 17:42 history edited IMeasy CC BY-SA 3.0
added 32 characters in body
Jun 26, 2011 at 15:51 comment added roy smith As motivation for related questions, Mumford gives, in his first paper on Prym varieties, an explicit Pfaffian of linear forms, which defines the tangent cone to the theta divisor of a Prym variety precisely when that Pfaffian is not identically zero. When this occurs is more complicated however and was only settled some 25 years later.
Jun 26, 2011 at 3:48 comment added Gjergji Zaimi Please try to improve the question! As it stands, it might (and probably should) get closed for lack of clarity, motivation etc.
Jun 25, 2011 at 20:47 answer added Francesco Polizzi timeline score: 18
Jun 25, 2011 at 17:26 comment added Qiaochu Yuan What is a Pfaffian polynomial?
Jun 25, 2011 at 17:06 answer added Bruce Westbury timeline score: 13
Jun 25, 2011 at 16:41 history asked IMeasy CC BY-SA 3.0