Timeline for What is Gelfand-Tsetlin basis for an irreducible representation of sl(n)?
Current License: CC BY-SA 3.0
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| Jun 25, 2011 at 5:11 | comment | added | Victor Protsak | The difference is that $\mathfrak{gl}_n,$ unlike $\mathfrak{sl}_n,$ has one-dimensional center (scalar matrices). Thus every simple $\mathfrak{gl}_n$-module remains simple under restriction to $\mathfrak{sl}_n$, but the same $\mathfrak{sl}_n$-module can be extended to a one-parameter family of $\mathfrak{gl}_n$-modules by making the center act as an arbitrary scalar. | |
| Jun 24, 2011 at 19:47 | comment | added | Melania | Thank you. How to reduce $gl_n$ module to $sl_n$ module? | |
| Jun 24, 2011 at 5:32 | history | edited | Victor Protsak | CC BY-SA 3.0 |
added 266 characters in body
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| Jun 24, 2011 at 5:23 | history | answered | Victor Protsak | CC BY-SA 3.0 |