Skip to main content
12 events
when toggle format what by license comment
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jun 26, 2011 at 5:55 comment added Torsten Ekedahl Yes, that's it.
Jun 24, 2011 at 12:55 comment added James D. Taylor I guess that's what you meant: to do the cohomology version of Poincare, and then to use the universal coefficient formula to get the usual (homology on one side, cohomology on the other) version.
Jun 24, 2011 at 12:44 comment added James D. Taylor Okay, so you pointed out two problems: one, the dualizing sheaf should be $K[n]$ rather than $K[-n]$, and the other that my formula for the homology is wrong. So can this be interpreted as a proof of the cohomology version of Poincare duality: $H^k(X,K)=[K,K[k]]=$by my interpretation of the dualizing sheaf $=[K[k],K\otimes K[n]]=[K[k],K[n]]=[K,K[n-k]]=H^{n-k}(X,K)$? Or is there a fault in that proof?
Jun 24, 2011 at 5:12 answer added Greg Friedman timeline score: 2
Jun 24, 2011 at 5:10 comment added Torsten Ekedahl Sorry, didn't look closely at what you said. You are also wrong about the homology, your formula for $H_k(X,\mathbb E)$ couldn't be OK as homology should be covariant in $\mathbb E$. The Verdier version of Poincaré duality is usually formulated purely in terms of cohomology just as is Serre duality. To get the usual topological version one combines this with the universal coefficient formula.
Jun 24, 2011 at 4:44 comment added James D. Taylor And even if by magic that were true, my interpretation of the dualizing sheaf would be wrong... (otherwise cohomology would be periodic)
Jun 24, 2011 at 4:36 comment added James D. Taylor If $D_X$ were $K[n]$ in the Poincare case, it still wouldn't make sense... I guess the only thing that would would be $H^k(X,K) \cong [K[k],K[n]]$, but I don't know how to make that fit with anything...
Jun 24, 2011 at 4:24 comment added Torsten Ekedahl You should not have different signs in the shifts for Serre and Poincaré duality, in fact the shifts should be exactly the same. The conventions used for shifts (whether a positive shift is to the right or the left) is confusing (at least to me) and my guess is that you have found sources that uses different conventions (which is wrong I think there is only one generally accepted convention only I can never remember which it is).
Jun 24, 2011 at 4:02 history edited James D. Taylor CC BY-SA 3.0
added 3 characters in body
Jun 24, 2011 at 2:37 history edited James D. Taylor CC BY-SA 3.0
added 3 characters in body
Jun 24, 2011 at 2:21 history asked James D. Taylor CC BY-SA 3.0