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Jun 23, 2011 at 8:45 history edited S. Carnahan CC BY-SA 3.0
Expansion; added 592 characters in body; edited body
Jun 22, 2011 at 18:57 comment added Kevin Buzzard Alternatively: clearly the series converges for $|q|<1$, because $\lambda$ is a function on the upper half plane. However the coefficients are integers and $\lambda$ is surely known not to be a polynomial (I believe this is a general fact about modular functions), so clearly the function will never converge absolutely for $|q|=1$ and you're home.
Jun 22, 2011 at 12:27 vote accept Ariyan Javanpeykar
Jun 22, 2011 at 12:25 comment added Ariyan Javanpeykar I see Junkie made the same comment.
Jun 22, 2011 at 12:05 comment added Ariyan Javanpeykar So, for all tau in the complex upper half plane, we have that lambda(tau) = sum a_j q(tau)^j? (Here I use that |q(tau)| < R if and only if Im(tau) > log(1/R)/(2pi) .)
Jun 22, 2011 at 11:07 history answered S. Carnahan CC BY-SA 3.0