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Jun 26, 2011 at 16:16 comment added Johan Öinert Jack, you are of course right. Thanks for pointing this out. I have tried to make my "answer" a bit more clear now.
Jun 26, 2011 at 16:11 history edited Johan Öinert CC BY-SA 3.0
Pointed out that this is not an answer to the original question.
Jun 21, 2011 at 20:27 comment added Jack Schmidt I think by "unital ring" you mean "unital commutative (associative) ring". Otherwise, there are obviously ring homomorphisms. Similarly tr(AB) = tr(BA) requires commutativity (it has counterexamples in every non-commutative ring). Unfortunately, the original question specifically allows matrix rings over non-commutative rings, so this doesn't answer the question.
Jun 21, 2011 at 16:18 history edited Johan Öinert CC BY-SA 3.0
Remarked that the proof holds for higher order Weyl algebras.
Jun 21, 2011 at 16:08 history answered Johan Öinert CC BY-SA 3.0