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gowers
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With your corrected question you are asking, in a strange way, for the number of arithmetic progressions of length 3 in A. There is a well-known example of Behrend of a set of size $n/\exp(c\sqrt{\log n})$ that contains no non-degenerate APs of length 3. So the answer to your question is no.

Edit: now that you have rephrased your question explicitly to be about arithmetic progressions of length 3, the words "in a strange way" no longer apply above. Indeed, the whole of the first sentence is rendered redundant (but I'll leave it there for the historical record).

With your corrected question you are asking, in a strange way, for the number of arithmetic progressions of length 3 in A. There is a well-known example of Behrend of a set of size $n/\exp(c\sqrt{\log n})$ that contains no non-degenerate APs of length 3. So the answer to your question is no.

With your corrected question you are asking, in a strange way, for the number of arithmetic progressions of length 3 in A. There is a well-known example of Behrend of a set of size $n/\exp(c\sqrt{\log n})$ that contains no non-degenerate APs of length 3. So the answer to your question is no.

Edit: now that you have rephrased your question explicitly to be about arithmetic progressions of length 3, the words "in a strange way" no longer apply above. Indeed, the whole of the first sentence is rendered redundant (but I'll leave it there for the historical record).

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gowers
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With your corrected question you are asking, in a strange way, for the number of arithmetic progressions of length 3 in A. There is a well-known example of Behrend of a set of size $n/\exp(c\sqrt{\log n})$ that contains no non-degenerate APs of length 3. So the answer to your question is no.