Skip to main content
added 72 characters in body
Source Link
Ian Agol
  • 68.9k
  • 3
  • 194
  • 358

It's a conjecture that surface groups are characterized (among infinite groups, with the exception of $\mathbb{Z}/2\mathbb{Z}$) by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.


Addendum July 2024: This conjecture has been proved for 2-generator groups:

Further addendum July 2024: Recently, this conjecture has been proved in full generality. More precisely, every one-relator group such that every subgroup of infinite index is free is either a free group or a surface group. (The related conjecture, that every residually finite one-relator group with every finite-index subgroup one-relator must be either free, a surface group or a Baumslag--Solitar group, remains open.)

  • Henry Wilton, Surface groups among cubulated hyperbolic and one-relator groups, arXiv:2406.02121.

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.


Addendum July 2024: This conjecture has been proved for 2-generator groups:

Further addendum July 2024: Recently, this conjecture has been proved in full generality. More precisely, every one-relator group such that every subgroup of infinite index is free is either a free group or a surface group. (The related conjecture, that every residually finite one-relator group with every finite-index subgroup one-relator must be either free, a surface group or a Baumslag--Solitar group, remains open.)

  • Henry Wilton, Surface groups among cubulated hyperbolic and one-relator groups, arXiv:2406.02121.

It's a conjecture that surface groups are characterized (among infinite groups, with the exception of $\mathbb{Z}/2\mathbb{Z}$) by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.


Addendum July 2024: This conjecture has been proved for 2-generator groups:

Further addendum July 2024: Recently, this conjecture has been proved in full generality. More precisely, every one-relator group such that every subgroup of infinite index is free is either a free group or a surface group. (The related conjecture, that every residually finite one-relator group with every finite-index subgroup one-relator must be either free, a surface group or a Baumslag--Solitar group, remains open.)

  • Henry Wilton, Surface groups among cubulated hyperbolic and one-relator groups, arXiv:2406.02121.
Added reference to proof of conjecture.
Source Link
HJRW
  • 25.2k
  • 3
  • 68
  • 145

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.


Addendum July 2024: This conjecture has been proved for 2-generator groups2-generator groups:

Further addendum July 2024: Recently, this conjecture has been proved in full generality. More precisely, every one-relator group such that every subgroup of infinite index is free is either a free group or a surface group. (The related conjecture, that every residually finite one-relator group with every finite-index subgroup one-relator must be either free, a surface group or a Baumslag--Solitar group, remains open.)

  • Henry Wilton, Surface groups among cubulated hyperbolic and one-relator groups, arXiv:2406.02121.

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.


Addendum July 2024: This conjecture has been proved for 2-generator groups:

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.


Addendum July 2024: This conjecture has been proved for 2-generator groups:

Further addendum July 2024: Recently, this conjecture has been proved in full generality. More precisely, every one-relator group such that every subgroup of infinite index is free is either a free group or a surface group. (The related conjecture, that every residually finite one-relator group with every finite-index subgroup one-relator must be either free, a surface group or a Baumslag--Solitar group, remains open.)

  • Henry Wilton, Surface groups among cubulated hyperbolic and one-relator groups, arXiv:2406.02121.
Full reference including doi link, link to definition, formatting
Source Link
David Roberts
  • 35.5k
  • 11
  • 124
  • 349

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.

 

Addendum July 2024: This conjecture has been proved for 2-generator groups.2-generator groups:

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.

Addendum: This conjecture has been proved for 2-generator groups.

It's a conjecture that surface groups are characterized by being the only 1-relator groups such that every finite-index subgroup is also 1-relator and every infinite index subgroup is free.

 

Addendum July 2024: This conjecture has been proved for 2-generator groups:

Added new reference
Source Link
Ian Agol
  • 68.9k
  • 3
  • 194
  • 358
Loading
added 42 characters in body
Source Link
Ian Agol
  • 68.9k
  • 3
  • 194
  • 358
Loading
Source Link
Ian Agol
  • 68.9k
  • 3
  • 194
  • 358
Loading