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Jun 18, 2011 at 20:40 comment added user15871 Yes, I noticed that. Interestingly, I used round-about method to reach the solution yesterday, but that was not elegant and it was bothering me (solved for n=2, 3 and extrapolated from there by induction). But your approach is simple and elegant, and right use of Sherman-Morrison formula. Glad I posted the problem on this site.
Jun 18, 2011 at 20:34 comment added Ian Martin You might also want to rearrange the formulas I give to make it clearer that they work fine if one of the $x_{i}$ equals one. (Obviously the matrix is not invertible if two or more of the $x_{i}$ equal one.)
Jun 18, 2011 at 20:33 comment added user15871 Thanks Douglas for the reference. As I was working on the problem from your hint, Ian has already posted the solution! Thanks Ian. That's exactly I was looking for. Appreciate your help.
Jun 18, 2011 at 20:30 vote accept user15871
Jun 18, 2011 at 20:22 history answered Ian Martin CC BY-SA 3.0