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S Nov 6 at 9:50 history suggested Vladimir Sotirov CC BY-SA 4.0
Fixed typo of taking too many duals.
Nov 4 at 20:41 review Suggested edits
S Nov 6 at 9:50
Jun 26, 2011 at 6:10 history edited Torsten Ekedahl CC BY-SA 3.0
Added comment on divided powers
Jun 17, 2011 at 12:51 comment added Qiaochu Yuan @Andrew: the diagonal map is actually from $U$ to $U \oplus U$ and it's the obvious one $u \mapsto u \oplus u$ coming from the universal property.
Jun 17, 2011 at 12:51 vote accept Qiaochu Yuan
Jun 17, 2011 at 12:50 history edited Qiaochu Yuan CC BY-SA 3.0
deleted 2 characters in body
Jun 17, 2011 at 9:19 comment added Andrew Stacey Can you clarify one point for me? Can you write out the diagonal map $U \to U \otimes U$ on elements for me? I'm used to thinking of $\otimes$ as the coproduct of algebras (whence it has a codiagonal) so I'm having trouble seeing exactly how to write down the diagonal.
Jun 17, 2011 at 8:52 comment added S. Carnahan The distinction between the exterior and symmetric cases in the last paragraph is very interesting!
Jun 17, 2011 at 7:37 history answered Torsten Ekedahl CC BY-SA 3.0