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Jun 21, 2011 at 9:10 comment added joro For 3-full the only solutions I found are: 271^3 + 2^3 * 3^5 * 73^3=919^3 and 3^4 * 29^3 * 89^3 + 7^3 * 11^3 * 167^3=2^7 * 5^4 * 353^3
Jun 17, 2011 at 14:45 comment added joro @Gerry I couldn't find solution in the first 300 terms.
Jun 17, 2011 at 12:15 comment added Gerry Myerson The question is whether the sum of two coprime 4-full numbers can be 4-full. The first 4-full numbers are tabulated at oeis.org/A036967
Jun 17, 2011 at 11:15 history edited joro CC BY-SA 3.0
Deleted nonsense
Jun 17, 2011 at 10:10 comment added joro @J.C. Ottem Thank you! I think I begin understand the second equation. Strangely to me some conics gave abc triples with quality 1.2 - 1.3 so I wonder should I delete the second equation or rephrase it sanely for abc triples...
Jun 17, 2011 at 9:02 comment added J.C. Ottem @joro: The resulting conic curve is still homogenous, so there are lots of coprime integer solutions.
Jun 17, 2011 at 8:44 comment added joro Taylor thank you. Added "integer" solutions, coprime was in the OQ.
Jun 17, 2011 at 8:43 history edited joro CC BY-SA 3.0
integer solutions
Jun 17, 2011 at 8:14 comment added Taylor Dupuy For any fixed y and t this is still a rational curve and has an infinite number of solutions.
Jun 17, 2011 at 7:27 comment added joro Thank you Gjergji. Edited the question disallowing $\pm 1$
Jun 17, 2011 at 7:26 history edited joro CC BY-SA 3.0
Disallowed y,t $\pm 1$
Jun 17, 2011 at 7:12 comment added Gjergji Zaimi Of course, your last equation has infinitely many solutions, take $y=t=1$ and the rest a primitive pythagorean triple.
Jun 17, 2011 at 6:53 history asked joro CC BY-SA 3.0