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Dec 27, 2021 at 13:53 history edited LSpice CC BY-SA 4.0
Link to @TorstenEkedahl's comment while this is on the front page
Dec 3, 2021 at 18:55 comment added Alexey Muranov Sorry, but could someone please clarify for non-specialists which pairing is "the most natural" one according to Torsten's answer?
Jun 17, 2011 at 14:16 comment added Theo Johnson-Freyd @unknowngoogle: yes, that's a typo. @Scott: If you only care about normal vector spaces, then you certainly can do this. If you care about constructions that generalize to supervector spaces, or to any other not-very-concrete category, then you cannot. @Torsten: Ok, so I must have made an error. I've thought a lot more about the details in the symmetric algebra case, where I am sure that the Hopf map is not an iso in general.
Jun 17, 2011 at 12:53 comment added Qfwfq If you want to obtain the exterior algebra, I think the ideal by wich to quotient should be $\langle v_1\otimes v_2 + v_2\otimes v_1 \rangle$.
Jun 17, 2011 at 4:44 comment added Torsten Ekedahl With the correction made by Scott it always is an isomorphism, use that the exterior algebra takes directs sums to tensor products to reduce to dimension 1 where it is obvious.
Jun 17, 2011 at 3:08 comment added S. Carnahan I think your definition of exterior algebra needs to be changed when 2 is not invertible. The ideal should be generated by elements of the form $x \otimes x$.
Jun 17, 2011 at 2:37 history answered Theo Johnson-Freyd CC BY-SA 3.0