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S Oct 1, 2015 at 0:40 history edited მამუკა ჯიბლაძე CC BY-SA 3.0
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S Oct 1, 2015 at 0:40 history suggested Iosif Pinelis CC BY-SA 3.0
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Oct 1, 2015 at 0:20 review Suggested edits
S Oct 1, 2015 at 0:40
Sep 29, 2015 at 19:18 review Late answers
Oct 1, 2015 at 0:20
Jun 16, 2011 at 20:26 comment added Tom LaGatta That is a nice observation, pedro. If one is furthermore interested in any higher moments $\mathbb E (XY)^k$, then I suggest using the decomposition $Y = \tfrac{\rho \sigma_y}{\sigma_x}X + \sqrt{1-\rho^2}\sigma_y Z$ and using the independence of $X$ and $Z$. As Arkadiusz says, there is likely no known closed-form expression for the product, though in practice we can estimate probabilities using Chebyshev's inequality and arbitrary moments.
Jun 16, 2011 at 18:57 history answered cat_the_curiosity CC BY-SA 3.0