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Oct 2, 2021 at 18:03 history edited zeb CC BY-SA 4.0
replaced absolute value in denominator with positive part - not sure what I was thinking originally
Oct 2, 2021 at 17:25 comment added zeb @Mark In order to compute $j_{lin}(n)$, you need to solve a linear program - for $j_{lin}(P_n)$, this linear program has $2^n$ variables (however, it seems to be the case that there are always optimal solutions where only polynomially many of the variables are nonzero).
Oct 2, 2021 at 14:11 comment added Mark L. Stone Where does lLinear Programming come into the picture? It is only mentioned in the question title.
S Oct 2, 2021 at 7:27 history suggested Conifold CC BY-SA 4.0
Fixed broken link to Hagedorn's paper
Oct 2, 2021 at 4:42 review Suggested edits
S Oct 2, 2021 at 7:27
Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Apr 13, 2017 at 12:57 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Nov 29, 2011 at 21:20 answer added Fintan timeline score: -1
Jun 16, 2011 at 2:23 comment added Gerhard Paseman I think Hagedorn covers the prime 2 in his paper, and N Saradha has kindly given me a preprint which might help with (if not directly imply) your c_d = -c_2d for odd d. If you figure out the Hangman puzzle on my registered MathOverflow page, I invite you to email me so that I can tell you more of Saradha's work. I can also send you improved bounds ala Stevens, although not as good as Iwaniec has for large n. Gerhard "Ask Me About System Design" Paseman, 2011.06.15
Jun 16, 2011 at 1:29 history asked zeb CC BY-SA 3.0