Timeline for Torsion - subgroup and quotient
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 14, 2011 at 12:42 | answer | added | Andrei Jaikin | timeline score: 2 | |
| Jun 13, 2011 at 8:05 | comment | added | Tim Dokchitser | @Yiftach: You are right, thanks! I missed the word "subgroup" | |
| Jun 12, 2011 at 21:23 | answer | added | Yiftach Barnea | timeline score: 0 | |
| Jun 12, 2011 at 17:54 | comment | added | Yiftach Barnea | Tim, but do the torsion form a subgroup? I don't think so. Michael is not asking whether the torsion as a set is not closed but he also requires it to be a subgroup. | |
| Jun 12, 2011 at 17:40 | answer | added | Alves | timeline score: 0 | |
| Jun 11, 2011 at 11:51 | comment | added | Tim Dokchitser | I think $G=\ker(GL_2({\mathbb Z}_2)\to GL_2({\mathbb F}_2))$ is a pro-2 group for which (1) holds. The conjugates of $\scriptstyle\begin{pmatrix}1&0\cr0&-1\end{pmatrix}$, i.e. reflections, seem to generate topologically a finite index subgroup with plenty of non-torsion elements (maybe even the whole of $G$?) Don't know about (2) though. | |
| Jun 10, 2011 at 2:32 | history | asked | Michael | CC BY-SA 3.0 |