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Sep 4, 2011 at 2:42 answer added Noam D. Elkies timeline score: 2
Sep 3, 2011 at 20:33 comment added Noam D. Elkies Is it easy to outline the proof of $F(x_1) \geq \alpha/6$? That might give a start towards the more general problem you ask.
Sep 3, 2011 at 20:31 comment added Noam D. Elkies The size of $\alpha = \int_0^1 f(t) \phantom. dt$ is irrelevant: multiplying $f$ by a scalar $c$ preserves concavity and multiplies $F(x_1,\ldots,x_n)$ by the same $c$, so if a bound like $\alpha/(6n)$ holds for "small" $\alpha$ then it also holds without any such hypothesis.
Aug 20, 2011 at 18:35 answer added Trenton Osborn timeline score: 1
Jun 10, 2011 at 17:26 comment added Pietro Majer Note that for a fixed $f$, the function $F$ is $C^1$ in the variables $(x_1,\dots,x_n)$, even if $f$ is only integrable. There is a minimizer on the closed symplex {$0\le x_1 \le \dots\le x_n\le 1$} by compactness, and it verifies $0 < x_1 < \dots < x_n < 1$ provided $f$ is a.e. positive.
Jun 10, 2011 at 9:11 comment added Dirk Did you try to minimize $F$, e.g. by calculating its (sub-)derivatives with respect to all coordinates $x_i$ all solving the resulting equations?
Jun 9, 2011 at 20:01 history asked Jennifer Gao CC BY-SA 3.0