Timeline for Automorphisms of a weighted projective space
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Nov 3, 2013 at 22:21 | vote | accept | Puzzled | ||
Jul 7, 2011 at 16:17 | comment | added | Sasha | They are not isomorphic. | |
Jul 7, 2011 at 15:03 | comment | added | Puzzled | The weighted projective plane $\mathbb{P}(2,3,4)$ is ismorphic to $\mathbb{P}(1,2,3)$. Following your method I find different automorphisms for $\mathbb{P}(1,2,3)$ and $\mathbb{P}(2,3,4)$. Where am I wrong ? | |
Jun 13, 2011 at 13:52 | comment | added | mrw | ok. Thanks for the explanation. I also wanted to mention that the OP asked a slight different. He is asking what are the automorphisms that fix a smooth fixed point p. | |
Jun 12, 2011 at 19:53 | comment | added | Sasha | I consider the weighted projective space as the quotient stack of a vector space (minus zero) by the torus action. This is not the same as a quotient in the category of schemes, and so the automorphism group is different. In your example, the quotient stack is $P^1$ but with an orbifold $Z/2Z$ point. The automorphism group should preserve the point. If you compare the subgroup of $PGL(2)$ preserving a point to the group analogous to the one in my answer you will see they are the same. | |
Jun 12, 2011 at 19:08 | comment | added | mrw | I am a bit confused about this. Consider $\mathbb P(1,2)$. This should be the same as $\mathbb P^1$. So the automorphism group is $\mathbb PGL(2)$. But with the method you describe, wouldn't you get a different answer? | |
Jun 9, 2011 at 19:19 | history | answered | Sasha | CC BY-SA 3.0 |