Timeline for What functor does Grassmannian represent?
Current License: CC BY-SA 2.5
5 events
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Nov 26, 2009 at 15:28 | comment | added | Peter McNamara | OK so according to those notes you linked to, for any quotient of O^n_Y, being flat with Hilbert polynomial k is equivalent to being locally free of rank k. (Now I just have to work out why this is true) | |
Nov 25, 2009 at 20:54 | history | edited | Ilya Nikokoshev | CC BY-SA 2.5 |
jsmath bug
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Nov 25, 2009 at 6:37 | comment | added | Steven Sam | Peter: I don't think it matters if Y is Noetherian or not. I picked this stuff up from Aaron Bertram's notes: math.utah.edu/~bertram/courses/hilbert and looking back on it, I guess I was supposed to put an equivalence relation on those short exact sequences. | |
Nov 25, 2009 at 5:21 | comment | added | Peter McNamara | When Y is not noetherian, don't we want to replace the condition that the quotient F of O^n_Y is locally free with the condition that it is flat over Y? (I'm thinking here about the formulation of the Quot scheme, which really deserves to be mentioned explicitly somewhere in an answer to this question). | |
Nov 24, 2009 at 21:55 | history | answered | Steven Sam | CC BY-SA 2.5 |