Timeline for Symmetric Algebra [closed]
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 8, 2011 at 22:55 | history | closed |
Bruce Westbury Theo Johnson-Freyd Ben Webster♦ |
no longer relevant | |
| Jun 8, 2011 at 21:33 | comment | added | Qiaochu Yuan | Polynomials on $V$ are precisely elements of $S(V^{\ast})$ by the universal property of the symmetric algebra. There are no characteristic issues here. | |
| Jun 8, 2011 at 21:28 | answer | added | Bruce Westbury | timeline score: 1 | |
| Jun 8, 2011 at 21:23 | comment | added | Vladimir Dotsenko | Well, what prevents you from defining polynomial functions on $V$ as $S(V^*)$? It clearly makes sense: $V^*$ consists of all linear functions, and multiplying them to to create polynomials is a natural thing. Or are you worried about the possible side effects in positive characteristic? | |
| Jun 8, 2011 at 21:13 | history | asked | Paolo Antonini | CC BY-SA 3.0 |