Timeline for "Letters and Numbers" Numbers game
Current License: CC BY-SA 3.0
20 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 19, 2012 at 11:31 | answer | added | Musicos | timeline score: 1 | |
| Jun 9, 2011 at 5:55 | vote | accept | Shannon | ||
| Jun 8, 2011 at 1:59 | answer | added | Gerhard Paseman | timeline score: 1 | |
| Jun 7, 2011 at 22:54 | comment | added | Vince | I read the OP's question as having the 3-digit goal given in advance. | |
| Jun 7, 2011 at 19:25 | comment | added | Gerald Edgar | Wait: the 3-digit goal is given in advance? or not? | |
| Jun 7, 2011 at 15:25 | comment | added | Gerhard Paseman | Again, I should not use a small screen for this. The product of any 5 positive distinct integers is greater than 119. Gerhard "Wants A Bigger Screen Too" Paseman, 2011.06.07 | |
| Jun 7, 2011 at 15:21 | comment | added | Gerhard Paseman | As I read the question, the solver is required only to produce a number greater than 99: The product of any 5 positive numbers will do this. If instead you are asking that any number in the ramge 100-999 be produced, then you will likely need more digits. Robert Israel's post suggests to me that at least 7 numbers are needed. Gerhard "Ask Me About System Design" Paseman, 2011.06.07 | |
| Jun 7, 2011 at 15:09 | answer | added | Robert Israel | timeline score: 4 | |
| Jun 7, 2011 at 14:57 | history | edited | Shannon | CC BY-SA 3.0 |
Included non-identity condition in the question statement.
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| Jun 7, 2011 at 14:54 | comment | added | Shannon | @Gerald: You are not required to use all the numbers, but you can only use each number once. Also each number must be different. | |
| Jun 7, 2011 at 14:53 | comment | added | Gerald Edgar | With the one- and two-digit restrictions, suppose we have 1,1,1,99,99,99. What 3-digit number can you get? 99 (99/99+1+1+1)=365. Are we required to use all the numbers? | |
| Jun 7, 2011 at 14:48 | comment | added | Shannon | @Gerhard: Is there a proof of that? | |
| Jun 7, 2011 at 14:43 | comment | added | Andreas Blass | I'd interpret "2 digits" in the problem as meaning a number between 10 and 99, not something like 05. | |
| Jun 7, 2011 at 14:43 | history | edited | Shannon | CC BY-SA 3.0 |
I neglected to mention that they must be six *different* numbers. Also, I had mistakenly placed some restrictions on the size of the numbers, which I have removed.
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| Jun 7, 2011 at 14:40 | comment | added | Gerhard Paseman | 6 is the minimum, as suggested by the set 0,1,2,3,4,5. Gerhard "Ask Me About System Design" Paseman, 2011.06.07 | |
| Jun 7, 2011 at 14:36 | comment | added | Gerhard Paseman | qpi is smartphone for 108. Gerhard "Wants A Bigger, Smarter Keyboard" Paseman, 2011.06.07 | |
| Jun 7, 2011 at 14:35 | comment | added | Shannon | Sorry, I meant any six numbers subject to the restrictions on the show, so six different numbers. So the 6-tuple (1,1,1,1,1,1) is not allowed. | |
| Jun 7, 2011 at 14:32 | comment | added | Gerhard Paseman | Ed Pegg Jr. wrote on the "one complexity" of a number, which is the least number of ones needed to produce the number where only addition and multiplication are allowed. The least complex number greater than 100 is qpi which takes 13 ones to produce in this way. Guy's Unsolved Problems In Number Theory has some more on this problem. Gerhard "Ask Me About System Design" Paseman, 2011.06.07 | |
| Jun 7, 2011 at 14:18 | comment | added | Granger | Given 1,1,1,1,1,1, I don't think you can get higher than 9, so no. You can experiment here crosswordtools.com/numbers-game | |
| Jun 7, 2011 at 13:53 | history | asked | Shannon | CC BY-SA 3.0 |