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k->h in formula, to avoid confusion
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Ale De Luca
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I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2k+1}=\frac{1}{2^{2k+2}(2k+2)} \sum_{q=0}^k \binom{2k+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{k+1-q}-1\right]$$$$P_{2h+1}=\frac{1}{2^{2h+2}(2h+2)} \sum_{q=0}^h \binom{2h+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{h+1-q}-1\right]$$ where the $B_{2q}$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).

I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2k+1}=\frac{1}{2^{2k+2}(2k+2)} \sum_{q=0}^k \binom{2k+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{k+1-q}-1\right]$$ where the $B_{2q}$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).

I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2h+1}=\frac{1}{2^{2h+2}(2h+2)} \sum_{q=0}^h \binom{2h+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{h+1-q}-1\right]$$ where the $B_{2q}$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).

2 q -> 2q
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Allen Knutson
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I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2k+1}=\frac{1}{2^{2k+2}(2k+2)} \sum_{q=0}^k \binom{2k+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{k+1-q}-1\right]$$ where the $B_2q$$B_{2q}$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).

I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2k+1}=\frac{1}{2^{2k+2}(2k+2)} \sum_{q=0}^k \binom{2k+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{k+1-q}-1\right]$$ where the $B_2q$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).

I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2k+1}=\frac{1}{2^{2k+2}(2k+2)} \sum_{q=0}^k \binom{2k+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{k+1-q}-1\right]$$ where the $B_{2q}$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).

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Ale De Luca
  • 393
  • 2
  • 12

I'm not totally sure this fully answers your questions, but such relations are known for odd values of $k$: $$P_{2k+1}=\frac{1}{2^{2k+2}(2k+2)} \sum_{q=0}^k \binom{2k+2}{2q} (2-2^{2q})~ B_{2q} ~\left[(8P_1+1)^{k+1-q}-1\right]$$ where the $B_2q$'s are Bernoulli numbers (see Faulhaber's formula on Wikipedia).