Timeline for Now that I got a mutant-discriminating invariant...
Current License: CC BY-SA 3.0
2 events
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Jun 7, 2011 at 11:49 | comment | added | Hauke Reddmann | Oh. Seems I underestimated the "technicalities". (BTW, does VI(K1#K2)=VI(K1)*VI(K2) hold like for a knot polynomial, or does the step above has the effect of a logarithm and it is "+" instead of "*"?) | |
Jun 6, 2011 at 18:46 | history | answered | Noah Snyder | CC BY-SA 3.0 |