Timeline for Does the fact that this vector space is not isomorphic to its double-dual require choice?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| S May 2, 2017 at 20:01 | history | suggested | Matemáticos Chibchas | CC BY-SA 3.0 |
Improved formatting
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| May 2, 2017 at 19:54 | review | Suggested edits | |||
| S May 2, 2017 at 20:01 | |||||
| Jun 8, 2011 at 19:20 | comment | added | Ron Maimon | Thanks, sorry for the lapse. I must confess that it was initially surprising to me that V double dual is V (assuming probability is not contradictory, which I think one always should). The argument I found is too ad-hoc though--- there should be a simple non-measurable set. I will clean the answer up to remove the redundant assumption. | |
| Jun 6, 2011 at 18:44 | history | edited | Ron Maimon | CC BY-SA 3.0 |
format
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| Jun 6, 2011 at 18:43 | comment | added | Goldstern | If every subset of R is measurable, then there are no nonprincipal ultrafilters. (By symmetry, an ultrafilter would have to have measure 1/2, but by this is impossible for a tail set.) | |
| Jun 6, 2011 at 18:32 | history | edited | Ron Maimon | CC BY-SA 3.0 |
fix mistake
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| Jun 6, 2011 at 8:32 | history | answered | Ron Maimon | CC BY-SA 3.0 |