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Jan 29, 2018 at 18:02 history edited Gerald Edgar CC BY-SA 3.0
deleted 7 characters in body
Jan 29, 2018 at 17:54 history edited Gerald Edgar CC BY-SA 3.0
added 35 characters in body
S Jan 29, 2018 at 17:06 history suggested jeq CC BY-SA 3.0
Copied image to imgur.com, as it was not being displayed because of the new https rule. (There is still another broken image; the Wayback Machine does not help.)
Jan 29, 2018 at 16:49 review Suggested edits
S Jan 29, 2018 at 17:06
Jun 9, 2011 at 20:37 comment added fedja It took more than one evening but by now (I believe that) I have a proof. I'll try to update my answer as soon as I have more computer time (I'm traveling right now, so it is not always easy to find a quiet place and time; the proof is a bit long, so maybe I'll write piece after piece bumping the post :). Let's see if I'll make more silly mistakes).
Jun 6, 2011 at 12:51 comment added fedja Ah, you're right! $D(0)$ is undefined, so I need 3 strictly positive points on the line (the dip instead of the hump). It is also easy when you have more than 2 summands (I don't know if it is meaningful, but $D'\ge 0$ works for every number) but for 2 it may be, indeed, impossible. I'll check by the evening and update the post :).
Jun 6, 2011 at 4:13 history edited Gerald Edgar CC BY-SA 3.0
added 29 characters in body
Jun 6, 2011 at 4:06 history answered Gerald Edgar CC BY-SA 3.0