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Jun 9, 2011 at 3:04 comment added Saikat Biswas Indeed. We know that, over $U$, $\mathcal{B}^0[p]$ is quasi-finite flat and separated, and it has a finite flat subgroup scheme, say $F\mathcal{B}^0[p]$. As I mentioned, I suppose that there is a closed immersion of $F\mathcal{B}^0[p]$ into $\mathcal{A}^0[p]$ but not sure exactly why
Jun 8, 2011 at 23:21 comment added Kevin Buzzard Oh -- maybe I'm misunderstanding. What is "the finite flat multiplicative type subgroup-scheme of $B^0[p]$"? Note that $B^0[p]$ is not flat. I guess it will contain as a subscheme some flat lifting of the special fibre though, which will I guess then be a closed subscheme of $A^0[p]$. Maybe that's what you're asking, in which case it sounds true to me.
Jun 8, 2011 at 20:02 comment added Kevin Buzzard I don't think it can be true because the generic fibres are isomorphic and dense, so how can anything be a closed subgroup of anything?
Jun 8, 2011 at 6:34 comment added Saikat Biswas Thank you for the counterexample. Having read Section 1 of Mazur's Rational Isogenies paper, I tried to work out some of the details in your counterexample and (although I'm not entirely sure I have it right) it seems that over $\mathbb{Z}_{\ell}$, there might be a closed immersion of the finite flat multiplicative type subgroup-scheme of $\mathcal{B}^0[p]$ into $\mathcal{A}^0[p]$. Is this true?
Jun 5, 2011 at 8:12 history undeleted Kevin Buzzard
Jun 5, 2011 at 8:12 history edited Kevin Buzzard CC BY-SA 3.0
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Jun 5, 2011 at 7:57 history edited Kevin Buzzard CC BY-SA 3.0
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Jun 5, 2011 at 7:50 history deleted Kevin Buzzard
Jun 5, 2011 at 7:41 history answered Kevin Buzzard CC BY-SA 3.0