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Jun 5, 2011 at 14:18 vote accept jsb
Jun 4, 2011 at 10:41 comment added Michael Renardy In the example above D is a core for A and B. It is not a core for A+B.
Jun 4, 2011 at 7:43 comment added Dima Shlyakhtenko It may be helpful to note that the reason counterexamples exist is that the intersection of the two domains may be smaller than each of the domains; and if $A$ is ess. self-adjoint with domain $D$ and $D_0\subset D$ is dense, the closure of the restriction of $A$ to $D_0$ may not coincide with $A$. (If the closure of the restriction of $A$ to $D_0$ is $A$ one sometimes says that $D_0$ is a core for $A$). So your $A+B$ will be ess. self-adjoint if you assume that there is a common core for $A$ and $B$.
Jun 4, 2011 at 7:34 history answered Michael Renardy CC BY-SA 3.0