Timeline for Is there a good explanation for this fact on pairwise independent variables?
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| Jun 2, 2011 at 22:27 | comment | added | fedja | Elaborating on this: If we have 0000 with probability $a$, then E[X1+X2+X3+X4]=2, EE[(X1+X2+X3+X4)^2]=5, so, by Cauchy 5(1-a)\ge 4 and a\le 1/5. Probably, that is not tight, but it is good enough. | |
| Jun 2, 2011 at 21:22 | history | answered | Ori Gurel-Gurevich | CC BY-SA 3.0 |