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May 10, 2021 at 2:46 comment added Sándor Kovács @ThomasNevins: Yes, this is correct. My comment was about your parenthetical remark.
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jun 3, 2011 at 6:14 comment added naf All quotient singularities are $\mathbb{Q}$-factorial.
Jun 2, 2011 at 21:57 comment added Thomas Nevins Hi Sandor, Thanks for the comment---if I'm not mistaken this is true for cyclic quotient singularities, no? [That's why I referred to your earlier MO answer that spells this out.] Though if not, then I'll correct my answer...in any case, again thanks for the clarification!
Jun 2, 2011 at 7:43 comment added Sándor Kovács ps: See an example that shows that this can actually happen in my answer.
Jun 2, 2011 at 7:30 comment added Sándor Kovács @Tom: for your last statement you also need the singularity to be $\mathbb Q$-factorial. Otherwise it might admit a small resolution in which case there are no discrepancies at all.
Jun 1, 2011 at 14:31 comment added naf A smooth point is both Gorenstein and terminal :)
Jun 1, 2011 at 13:07 history answered Thomas Nevins CC BY-SA 3.0