Timeline for Schwartz space inequality
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Mar 28, 2012 at 20:18 | answer | added | Bazin | timeline score: 2 | |
| Jun 3, 2011 at 7:40 | comment | added | agt | @Feynmaniac: About an approach which doesn't separate the two cases $|x|\ge 2|y|$ and $|x|\le 2|y|$: couldn't it be possible the following proof? 1)use the triangle inequality $|x|\le |y|+|x-y|$, 2)apply the binomial formula to $(|y|+|x-y|)^l$, 3)apply the hypothesis on $g$, and finally $|y|^k\le(1+|y|)^l$, for any $y\in\mathbb{R}$ and $0\le k\le l$. | |
| Jun 2, 2011 at 6:48 | comment | added | Feynmaniac | @Piero D'Ancona: I'm mostly having trouble with finding where to use the two cases $|x|\ge 2|y|$ and $|x|\le 2|y|$. Any help? | |
| Jun 1, 2011 at 14:25 | history | edited | Mark Meckes | CC BY-SA 3.0 |
Corrected spelling of Schwartz
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| Jun 1, 2011 at 11:04 | comment | added | Piero D'Ancona | $$(1+|x-y|)^{-1} \le \frac {1+|y|}{1+|x|}$$ | |
| Jun 1, 2011 at 10:53 | history | edited | agt |
edited tags
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| Jun 1, 2011 at 10:25 | history | asked | Feynmaniac | CC BY-SA 3.0 |