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May 30, 2011 at 23:08 comment added Pietro Majer yes sorry, a typo.
May 30, 2011 at 21:44 answer added Mihaela timeline score: 0
May 30, 2011 at 21:16 comment added Michael Renardy I get $u'=u^2(1-fu)$.
May 30, 2011 at 17:57 comment added Pietro Majer Also note that $u:=1/y$ solves the ODE in normal form $u'=u^2(u-f)$, which suggest to translate your problem in terms of $u$.
May 30, 2011 at 14:35 answer added Michael Renardy timeline score: 1
May 30, 2011 at 10:41 history edited Pietro Majer CC BY-SA 3.0
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May 30, 2011 at 7:22 history edited agt
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May 30, 2011 at 6:03 history asked Rosa CC BY-SA 3.0