Timeline for General integer solution for $x^2+y^2-z^2=\pm 1$
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 15, 2011 at 9:50 | vote | accept | Victor Kuliamin | ||
| Jun 15, 2011 at 9:50 | |||||
| Jun 15, 2011 at 9:48 | vote | accept | Victor Kuliamin | ||
| Jun 15, 2011 at 9:49 | |||||
| May 26, 2011 at 2:33 | history | edited | Gerry Myerson | CC BY-SA 3.0 |
added 546 characters in body
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| May 25, 2011 at 17:02 | comment | added | Aaron Meyerowitz | Nice! but You mean $b=x-z$ | |
| May 25, 2011 at 13:35 | comment | added | Klaus Draeger | Looks good. One way of getting there is setting $a:=x+z, b:=x-y$ to obtain $ab=(1+y)(1-y)$, so that there must be $r,s,t,u$ with $rs=a,tu=b,1+y=rt,1-y=su$. | |
| May 25, 2011 at 12:50 | history | answered | Gerry Myerson | CC BY-SA 3.0 |