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I guess $p=char(k)$$p=\operatorname{char}(k)$. For another (unified) proof of Tate's theorem (that works for primes $\ell\ne p$ and $\ell=p$) see arXiv:0711.1615[matharXiv:0711.1615 [math.AG]; MR2484084 (2010a:11117).
I guess $p=char(k)$. For another (unified) proof of Tate's theorem (that works for primes $\ell\ne p$ and $\ell=p$) see arXiv:0711.1615[math.AG]; MR2484084 (2010a:11117).
I guess $p=\operatorname{char}(k)$. For another (unified) proof of Tate's theorem (that works for primes $\ell\ne p$ and $\ell=p$) see arXiv:0711.1615 [math.AG]; MR2484084 (2010a:11117).
I guess $p=char(k)$. For another (unified) proof of Tate's theorem (that works for primes $\ell\ne p$ and $\ell=p$) see arXiv:0711.1615[math.AG]; MR2484084 (2010a:11117).
