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May 24, 2011 at 22:04 vote accept Memming
May 24, 2011 at 22:04 comment added Memming Correct. Well, $(i,j)$ for column, $(k,l)$ for row, but that's not important. The Kronecker product of $C_{i,k}$ and $C_{j,l}$ is correct. Thanks.
May 24, 2011 at 21:11 comment added Federico Poloni I think so, unless I'm totally misunderstanding your notation. The pair $(i,j)$ forms the row index of the large matrix, doesn't it?
May 24, 2011 at 19:16 comment added Memming If $C_{(i,j),(k,l)}=\rho \alpha_x^{∣i−j∣} \alpha_x^{∣k−l∣}$, then I would agree, but the indices are a bit mixed. Does it still hold?
May 24, 2011 at 7:06 history answered Federico Poloni CC BY-SA 3.0