Timeline for group scheme neither affine, nor an abelian variety
Current License: CC BY-SA 3.0
3 events
when toggle format | what | by | license | comment | |
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May 18, 2011 at 13:21 | comment | added | Zoran Skoda | The ground field is required to be perfect in the Chevalley theorem. | |
May 18, 2011 at 10:18 | comment | added | Marc Palm | But at least, we have something close to that. See en.wikipedia.org/wiki/Chevalley_theorem. | |
May 18, 2011 at 10:16 | history | answered | Bugs Bunny | CC BY-SA 3.0 |