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May 18, 2011 at 20:19 comment added user13113 Yah, I overlooked your comment on that the first time. Sorry 'bout that.
May 18, 2011 at 13:39 vote accept Ajay Patwardhan
May 18, 2011 at 13:38 comment added Ajay Patwardhan Thanks. I did realize that $R/\frak{m}$ is zero dimensional (which is how I concluded that the dimensiona criterion will hold for any associated prime $p$. What I failed to realize was that this would imply $p=0$.
May 18, 2011 at 7:02 history answered user13113 CC BY-SA 3.0