Timeline for Quotient of smooth algebraic variety by proper free action of algebraic group
Current License: CC BY-SA 3.0
9 events
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| Jun 18, 2016 at 11:32 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
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| May 17, 2011 at 20:21 | comment | added | Jonathan | Some kind of holomorphic slice theorem would imply this (though you might need additional hypotheses). See Sjamaar's paper here: jstor.org/pss/2118628 | |
| May 17, 2011 at 16:18 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
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| May 17, 2011 at 15:48 | vote | accept | Nail | ||
| May 17, 2011 at 15:12 | comment | added | Nail | Thanks! It's very helpful. How about this: Let G be complex Lie group acting on a complex manifold M. Assume the action is proper and free. Is the orbit space M/G a complex manifold? It is clear that M/G is at least an almost complex manifold. What's less clear, though I believe true, is that the almost complex structure is integrable. Does anyone has a source? Thanks! | |
| May 17, 2011 at 14:35 | comment | added | David E Speyer | In characteristic zero, $\mathbb{G}_a$ has no nontrivial proper algebraic subgroups. So fixed point free does imply free in this case. | |
| May 17, 2011 at 14:24 | comment | added | Jonathan | Free implies fixed point free but not vice versa. Do they have an example of a free action where the quotient is bad? | |
| May 17, 2011 at 14:05 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
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| May 17, 2011 at 13:58 | history | answered | Francesco Polizzi | CC BY-SA 3.0 |