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May 12, 2011 at 5:22 comment added Remke Kloosterman The weights for $H^{2n−i}(X_{smooth})$ lie in $[2n−i,4n−2i]$, therefore the weights for $H^{2n−i}(X_{smooth})^∗(n)$ lie in $[2i−2n,i]$. If $i>2 dim X_{sing}+1$ and $i>n$ this yields a non-trivial bound on the weights for $H^i_c(X)$ and $H^i(X)$.
May 12, 2011 at 0:11 comment added shenghao Can you explain to me how $H^i(X)=H^i_c(X_{sm})$ will limit weights? Thanks.
May 11, 2011 at 19:28 history answered Remke Kloosterman CC BY-SA 3.0