Timeline for What does the space induced by this unusual metric(?) on R/Z look like?
Current License: CC BY-SA 3.0
5 events
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May 11, 2011 at 17:52 | comment | added | Roland Bacher | Right. Add $\epsilon$ everywhere. (I guess one can find a nice way related to proportions but this requires probably some trial and error. My first attempt was too naive.) | |
May 11, 2011 at 15:47 | comment | added | Alexander Woo | These choices don't satisfy the triangle inequality: $d(0,1/12)>d(0,5/12)+d(1/12,5/12)$. | |
May 11, 2011 at 12:18 | comment | added | Roland Bacher | A perhaps pleasant choice is given by $\alpha_5=2\epsilon$, $\alpha_4=3\epsilon$, $\alpha_2=4\epsilon$, $\alpha_3=5\epsilon$, $\alpha_1=6\epsilon$, $\alpha_6=7\epsilon$ where $\epsilon$ is small and positive. Justification: One wants a large (relative) distance if one is out of pitch (this is achieved by $\epsilon$ small). A more or less "rational" choice of distance is then to consider a distance proportional to $a+b$ if an interval consists of two notes with frequencies (roughly) proportional to $a/b2^{\mathbb Z}$. | |
May 11, 2011 at 9:32 | history | edited | Roland Bacher | CC BY-SA 3.0 |
added 198 characters in body
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May 11, 2011 at 9:13 | history | answered | Roland Bacher | CC BY-SA 3.0 |