Timeline for Products of Ideal Sheaves and Union of irreducible Subvarieties
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 13, 2011 at 9:41 | vote | accept | Jesko Hüttenhain | ||
| May 13, 2011 at 9:41 | vote | accept | Jesko Hüttenhain | ||
| May 13, 2011 at 9:41 | |||||
| May 11, 2011 at 16:03 | comment | added | Karl Schwede | I agree, you are right Sasha. One needs some assumptions certainly. | |
| May 11, 2011 at 12:16 | comment | added | Sasha | Karl, at least we have to assume something --- I have added a simple nontransversal example --- two lines in $A^3$ intersecting at a point. | |
| May 11, 2011 at 12:14 | history | edited | Sasha | CC BY-SA 3.0 |
added 761 characters in body
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| May 11, 2011 at 11:15 | comment | added | Karl Schwede | Sasha, that's true, but I guess it's not clear that we get to assume that. | |
| May 11, 2011 at 3:04 | comment | added | Sasha | Karl, transversality gives vanishing. If $Z_1 \cap Z_2$ is transversal to $Z_3$ then there are no tors. | |
| May 11, 2011 at 2:13 | comment | added | Karl Schwede | Sasha, are you sure about the higher tors vanishing? Its not clear to me that say $O_{Z_1 \cap Z_2}$ has no higher tors with $Z_3$? | |
| May 11, 2011 at 1:46 | comment | added | Karl Schwede | The superscipt means take the tensor product in the derived category. Basically, instead of just tensor product, one also has all the Tor's and all this data, and more, is rolled into one object (obviously this is a slightly misleading lie for those who are experts). | |
| May 10, 2011 at 22:58 | comment | added | Jesko Hüttenhain | That looks very nice, could you explain to me what kind of operation $\otimes^L$ is, as opposed to the tensor product? I mean, what does the the superscript $L$ mean? I am not familliar with that notation. | |
| May 10, 2011 at 17:48 | history | answered | Sasha | CC BY-SA 3.0 |